Span, Linear Independence, and Basis
In this section, we will explore the concepts of span, linear independence, and basis in the context of vectors and vector spaces. This has a clear parallel to this page, where we discussed the same topics. However, this page will delve deeper into the concepts and provide a more advanced and abstract understanding of these topics.
Table of Contents
Linear Combinations and Span
A linear combination of vectors
A linear combination of vectors
where
The set of all possible linear combinations of a set of vectors
There's another way to think about the span of a set of vectors. Let
The span of a set of vectors
Alternatively, the span of a set of vectors can be defined as the intersection of all subspaces of
Where
The two different definitions differ in philosophical approach; the definition from linear combinations is a "bottom-up" approach from the vectors themselves, while the subspace definition is a "top-down" approach from sets bigger than the vectors.
Proof of Equivalence of Definitions
We can prove that the two definitions of span are equivalent. First, let's lay out our definitions:
Let
-
The set of all possible linear combinations of the vectors in
: -
The intersection of all subspaces of
that contain :
Generally, in order to show that two sets
-
Linear Combinations
Subspaces:Let
be a vector in the span of defined by linear combinations. Then, can be written as a linear combination of the vectors in :Since
, the vectors in are in the span of . By definition, all the subspaces on the right-hand side of the second definition contain . And since they are subspaces, they are closed under addition and scalar multiplication, meaning any linear combination of vectors in is in the subspace. Hence, for all subspaces that contain . -
Subspaces
Linear Combinations:This is a bit more abstract because we don't actually know what the subspaces are, so we cannot construct a concrete value for
. Nevertheless, a key insight can help us here.Consider some sets
, , and , and their intersection . If , then is in all three sets. This means that is a subset of , , and . Then, contains all the elements in , and similarly for and .Let's apply that here. The right-hand side with the subspaces contains the intersection of all subspaces that contain
. Call these subspaces . Now, the key insight is that the span of is another subspace that contains ; denote it as . Then, the span is just . But since the intersection must be contained in each subspace, it is also contained in the span.Thus,
defined by subspaces is a subset of defined by linear combinations.
Hence, we have shown that the two definitions of span are equivalent.
Linear Independence
A set of vectors
A set of vectors
is
Lemma: Span and Linear Independence
There is a close relationship between the concepts of span and linear independence. In particular:
If a vector space
Before we prove this lemma, let's understand the intuition behind it.